Series Problem Logical Reasoning – Page 5

Series 5

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 Question 1
The smallest 5-digit number exactly divisible by 41 is
 A 10041 B 10004 C 10045 D 10025 E none of these
 Question 2
The smallest 6-digit number exactly by 111 is
 A 111111 B 110011 C 100011 D 110101 E none of these
 Question 3
In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, what is the dividend ?
 A 4236 B 4306 C 4336 D 5336 E none of these
 Question 4
On dividing a number by 68, we get 269 as dividend and 0 as remainder. On dividing the same number by 67, what will be the remainder?
 A 0 B 1 C 2 D 3
 Question 5
On dividing a number by 56, we get 29 as remainder . On dividing the same number by 8, what will be the remainder ?
 A 4 B 5 C 6 D 7
 Question 6
On dividing a number by 357, we get 39 as remainder. On dividing the same number by 17, what will be the remainder?
 A 0 B 3 C 5 D 11
 Question 7
On dividing a number by 5, we get 3 as remainder. What will be the remainder when the square of this number is divided by 5 ?
 A 0 B 1 C 2 D 4
 Question 8
The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and 15 as remainder. What is the smaller number?
 A 240 B 270 C 295 D 360
 Question 9
In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 35 as quotient. What is the correct quotient ?
 A 0 B 12 C 13 D 20
 Question 10
On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is :
 A 10 B 11 C 12 D 13
 Question 11
On multiplying a number by 7, the product is a number each of whose digits is 3. The smallest such number is :
 A 47619 B 47719 C 48619 D 47649
 Question 12
The difference of the squares of two consecutive odd integers is divisible by which of the following integers ?
 A 3 B 4 C 6 D 7
 Question 13
The difference of the squares of two consecutive odd integers is divisible by which of the following integers ?
 A 3 B 6 C 7 D 8
 Question 14
If n is a natural number, then (6n² + 6n) is always divisible by :
 A 6 only B 6 and 12 both C 12 only D by 18 only
 Question 15
n is a whole number which when divided by 4 gives 3 as remainder. What will be the remainder when 2n is divided by 4 ?
 A 3 B 2 C 1 D 0
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